Soft a day ago

In the former the caller does not retain access to T until Fn returns.

  • andyferris a day ago

    I think I'm lost. If I give a mutable reference to a function... I can't access it (even read it) until it returns, no?

    What is different?

    • zbentley 7 hours ago

      Let's say a function "foo" calls "fn bar(_: &mut T) -> ()".

      When passing a mutable reference, the lifetime of the object is largely decided by "foo" (with some caveats).

      Now, let's say that "foo" instead calls "fn bar(_: T) -> T".

      When passing the object itself, the lifetime is largely decided/decide-able by "bar".

  • IshKebab a day ago

    That's true of mutable references too though isn't it? In fact lots of people have suggested they should really have been called "exclusive references", since you can actually mutate some objects through non-exclusive references (called "interior mutability" normally).