Comment by taeric
This makes it sound like it will always be the same permutation in the sample code, though? Or is the first item of a list not determined? (Or is that not what (x:xs) means? I was reading that as "x followed by more x's".)
This makes it sound like it will always be the same permutation in the sample code, though? Or is the first item of a list not determined? (Or is that not what (x:xs) means? I was reading that as "x followed by more x's".)