Comment by thehappypm

Comment by thehappypm 10 months ago

13 replies

I have a question about black holes, HN.

Let’s say you have a black hole. You fire a laser beam straight into it. Just by symmetry, shouldn’t it blueshift on the way in, gain some preposterous amount of energy — enough that it can escape?

karpierz 10 months ago

Light travels in a straight line - black holes don't "pull" light in, they change what a straight line looks like in the space around it.

The event horizon is the distance where all straight lines lead to the black hole.

kadoban 10 months ago

It will gain energy.

There _is_ no amount of energy it could gain to escape though. It goes no faster, gets no closer to escape. It just splats into the black hole and we'll never see it again no matter how much energy it started with or gained.

  • thehappypm 10 months ago

    From an outside observer, the black hole is finite in width though, though. and if the speed of light is constant, isnt that a contradiction? Or is a black hole somehow of infinite width?

    • kadoban 10 months ago

      It's not a contradiction because the path of the light enters the black hole event horizon but does not come back out.

      All paths end at the ~center of the black hole. We don't really know what's there, at the so-called singularity at the center, it may be impossible to know. But it's probably something that light can hit and stop existing, or even if it can't it'll be stuck there in some way or another.

      We know that the gravity (warping of spacetime) around a black hole is such that it cannot escape, even at light speed. What happens inside is less sure, but largely moot because none of it can ever affect anything outside of the event horizon ever again.

      (Hawking Radiation or something else may make this technically a lie, but it's close enough to the truth to last a few trillion years)

    • hollerith 10 months ago

      It is finite in circumference, yes, but its geometry is not the usual geometry so diameter does not equal circumference divided by pi.

itishappy 10 months ago

> Just by symmetry, shouldn’t it blueshift on the way in, gain some preposterous amount of energy — enough that it can escape?

Escape requires a certain critical speed (escape velocity), and light always travels at the speed of light regardless of it's energy, so light's ability to escape a black hole is not energy dependent. At some radius (the event horizon), space itself falls into a black hole faster than the speed of light, and that's sets a hard limit on everything's ability to escape.

Past the event horizon physics get weird. Time becomes finite and ends for all observers at a point in the future called the singularity. Everything falls towards this point, gaining preposterous amounts of energy. "Preposterous" here means infinite energy, and infinite density, really just a whole lot of infinities. Those infinities are problematic, and mean there's probably something non-infinite and uniquely interesting going on in there, but since nothing can escape the event horizon we'll likely never know.

  • thehappypm 10 months ago

    Here’s something else that I’m concerned with with about black holes. If a mass is one nanogram below that of a black hole, how similar is it to a black hole?

mystified5016 10 months ago

Yes, but only if the black hole is rotating. Fortunately, all known black holes do rotate.

There's a concept for using exactly this idea for interstellar propulsion. You fire a laser around a black hole, it gains energy, then hits you, imparting more kinetic energy than you spent firing the laser.

In essence, you're executing a gravity slingshot with photons.

trailynx 10 months ago

You might enjoy the Halo Drive idea [0]. From my (very layman) understanding this uses this principle for propelling a spacecraft - you just need a moving black hole nearby :)

[0] https://arxiv.org/abs/1903.03423